Komunikasi dalam jaringan

192.168.1.0/28

11111111.11111111.11111111.11110000

*Oktet =11111111 = 255

*Oktet =11111111=255

*Oktet =11110000=240

1.Jumplah subnet = 2 pangkat x =2 pangkat 4 =16 subnet

2.Jumplah host persubnet = 2 pangkat x-2

y=4 : 2 pangkat 4-2=16-2=14 host persubnet

3.BLOK SUBNET = 0,16,32,48,64,80,96,112,128,144,160,176,192

Subnet 1 = 192.168.1.1

192.168.1.2

192.168.1.3

192.168.1.4

192.168.1.5

192.168.1.6

192.168.1.7
192.168.1.8
192.168.1.9
192.168.1.10
192.168.1.11
192.168.1.12

Subnet 2 = 19.168.1.