192.168.1.0/28 11111111.11111111.11111111.11110000 *Oktet =11111111 = 255 *Oktet =11111111=255 *Oktet =11111111=255 *Oktet =11110000=240 1.Jumplah subnet = 2 pangkat x =2 pangkat 4 =16 subnet 2.Jumplah host persubnet = 2 pangkat x-2 y=4 : 2 pangkat 4-2=16-2=14 host persubnet 3.BLOK SUBNET = 0,16,32,48,64,80,96,112,128,144,160,176,192 Subnet 1 = 192.168.1.1 192.168.1.2 192.168.1.3 192.168.1.4 192.168.1.5 192.168.1.6 192.168.1.7 ...
